Free GCSE Maths lesson: Number

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Lesson 73 · GCSE / Key Stage 4 · Maths · Number

Error Intervals and Limits of Accuracy

Write the possible range of values behind rounded measurements.

Qualification: GCSEKey Stage 4Subject: MathsStrand: Number

GCSE specification fit

Error Intervals and Limits of Accuracy is part of GCSE Maths Number.

Write the possible range of values behind rounded measurements. Foundation pupils should find simple upper and lower bounds. Higher pupils should combine bounds in calculations, choose the extreme values that answer the exact question, and keep endpoint notation precise.

QualificationGCSE Mathematics
Key stageKey Stage 4
StrandNumber
Tier guidanceFoundation intervals; Higher bounds calculations

What you will learn

  • Find upper and lower bounds for rounded values.
  • Write error intervals with inequality notation.
  • Use bounds in calculations.
  • Decide when endpoints are included or excluded.
  • Choose upper or lower bounds for maximum and minimum results.
  • Interpret limits of accuracy in context.

Why this matters

Measurements in GCSE questions are often rounded. Bounds show the full range of possible exact values and protect against over-precise answers.

Prior knowledge

You should already be comfortable with:

  • Rounding.
  • Inequality symbols.
  • Decimals.
  • Substitution into formulae.

Clear explanation

Main idea

If a length is 8 cm to the nearest cm, the exact length is at least 7.5 cm but less than 8.5 cm. Write 7.5 ≤ x < 8.5. The lower end is included; the upper end is not, because 8.5 would round to 9 cm.

Method

Find the rounding unit first. Half of that unit gives the amount to subtract and add. For 4.6 cm to the nearest 0.1 cm, half the unit is 0.05 cm, so 4.55 ≤ x < 4.65.

Exam tip

For calculations, choose the bounds that make the requested result largest or smallest. For a fraction, the maximum often uses the largest numerator and smallest denominator; the minimum uses the smallest numerator and largest denominator.

Worked examples

Nearest ten

A number is 340 to the nearest 10.

Answer: Half of 10 is 5, so 335 ≤ x < 345.

Decimal interval

A length is 4.6 cm to the nearest 0.1 cm.

Answer: Half of 0.1 is 0.05, so 4.55 ≤ l < 4.65.

Area bounds

A rectangle is 6 cm by 4 cm to the nearest cm. Smallest possible area?

Answer: Use the smallest possible length and width: 5.5 × 3.5 = 19.25 cm².

Quick checks

Choose an answer, then check your thinking.

1. A length is 28 cm to the nearest cm. Which interval is correct?

2. To maximise a/b when a and b are both rounded, which bounds should you try?

Practice questions

Question 1

A parcel has mass 12 kg to the nearest kg. Write its error interval and explain why the upper endpoint is not included.

Reveal answer and marking guidance

Answer: 11.5 ≤ m < 12.5.

Marking: Half of 1 kg is 0.5 kg. Include 11.5 because it rounds to 12, but exclude 12.5 because it would round up to 13.

Question 2

A measured length is 4.6 cm to the nearest 0.1 cm. Find the lower bound and state the rounding unit you used.

Reveal answer and marking guidance

Answer: 4.55 cm.

Marking: The rounding unit is 0.1 cm, so half of the unit is 0.05 cm. Lower bound = 4.6 − 0.05 = 4.55 cm.

Question 3

A speed camera reading is recorded as 50 mph to the nearest 5 mph. Write the possible interval for the actual speed.

Reveal answer and marking guidance

Answer: 47.5 ≤ s < 52.5.

Marking: Half of 5 mph is 2.5 mph, so subtract and add 2.5. Use < at the upper bound because 52.5 would round to 55 mph.

Question 4

A square side length is 7 cm to the nearest cm. Find the smallest possible area, using the correct bound for the side length.

Reveal answer and marking guidance

Answer: 42.25 cm².

Marking: The smallest possible side length is 6.5 cm, so the smallest possible area is 6.5 × 6.5 = 42.25 cm².

Question 5

A distance is 18.4 km to the nearest 0.1 km. Write the error interval.

Reveal answer and marking guidance

Answer: 18.35 ≤ d < 18.45.

Marking: Half of 0.1 km is 0.05 km; include the lower bound and exclude the upper bound.

Question 6

A rectangle has length 9 cm and width 5 cm, both to the nearest cm. Find the largest possible area.

Reveal answer and marking guidance

Answer: 52.25 cm².

Marking: Use upper bounds 9.5 cm and 5.5 cm, then calculate 9.5 × 5.5 = 52.25.

Question 7

A distance is 40 m to the nearest metre and a time is 8.0 s to the nearest 0.1 s. Find the minimum possible speed.

Reveal answer and marking guidance

Answer: 39.5 ÷ 8.05 = 4.906... m/s, so about 4.91 m/s to 3 significant figures.

Marking: For minimum speed, use the smallest distance and the largest time.

Question 8

A rounded value is 0.072 to 3 decimal places. Write its error interval.

Reveal answer and marking guidance

Answer: 0.0715 ≤ x < 0.0725.

Marking: Three decimal places means the rounding unit is 0.001, so half the unit is 0.0005.

Question 9

A rounded value a is 12.4 to the nearest 0.1, and a rounded value b is 3.0 to the nearest 0.1. Find the maximum possible value of a ÷ b.

Reveal answer and marking guidance

Answer: 12.45 ÷ 2.95 = 249/59 = 4.2203..., so about 4.22 to 3 significant figures.

Marking: For the maximum quotient, use the upper bound for a and the lower bound for b. Keep the calculation unrounded until the final answer.

Question 10

A garden path is 8.2 m long to the nearest 0.1 m and 1.6 m wide to the nearest 0.1 m. Find the minimum possible area.

Reveal answer and marking guidance

Answer: 8.15 × 1.55 = 12.6325 m².

Marking: For the minimum area, use the lower bound of both measurements. Half of 0.1 m is 0.05 m, so the lower bounds are 8.15 m and 1.55 m.

Answers and marking guidance

The exact practice answers are hidden under each question so you can try first. For bounds questions, marks usually come from identifying the rounding unit, halving it correctly, writing a precise interval with ≤ and <, choosing the correct upper or lower bounds for any calculation, and keeping sensible units and accuracy in the final answer.

Common mistakes

  • Using a whole unit instead of half: nearest 10 means add and subtract 5, not 10.
  • Including the upper endpoint: 8.5 would round to 9, so write x < 8.5 rather than x ≤ 8.5.
  • Choosing the wrong extreme: maximum area uses largest length and largest width, but maximum speed uses largest distance and smallest time.
  • Rounding inside the bounds calculation: keep extra accuracy until the final requested answer.

Extension challenge

A distance is 120 m to the nearest 10 m and a time is 9.0 s to the nearest 0.1 s. Find the maximum possible speed in m/s, then explain which bounds you used.

Reveal answer

Example answer: Distance has upper bound 125 m and time has lower bound 8.95 s, so maximum speed is 125 ÷ 8.95 = 13.966... m/s, about 14.0 m/s to 3 significant figures. Use largest distance and smallest time because speed = distance ÷ time.

Exam-board guidance

Error Intervals and Limits of Accuracy appears within GCSE Maths number and measures content. Exact wording, tiering and calculator expectations can vary, but the core skill is the same: identify the rounding unit, form precise bounds, then choose the bounds that answer the question.

AQA GCSE Maths

Halve the rounding unit to form the interval, use ≤ on the lower bound and < on the upper bound, then choose bounds that make the requested result largest or smallest.

OCR GCSE Maths

State the rounding unit first, then check whether a calculation needs the largest possible numerator, smallest denominator, or another bounds combination.

Pearson Edexcel GCSE Maths

Do not round the bounds calculation too early; keep enough accuracy and include units in measurement answers.

Eduqas GCSE Maths

Explain what the interval means in words as well as symbols when the question asks for interpretation.

WJEC Wales

In Numeracy-style contexts, connect the interval to what the rounded measurement could actually have been before making a decision.

CCEA GCSE Maths

Use the unit structure to decide how much bounds work is expected, and make endpoint notation precise enough for method marks.

Next lesson

Next, continue with Percentages: Finding and Comparing.