Free GCSE Maths lesson: Probability

Free LessonsGCSE / Key Stage 4Maths → Listing Outcomes and Sample Space Diagrams

Lesson 56 · GCSE / Key Stage 4 · Maths · Probability

Listing Outcomes and Sample Space Diagrams

List outcomes systematically so none are missed or counted twice.

Qualification: GCSEKey Stage 4Subject: MathsStrand: Probability

GCSE specification fit

Listing Outcomes and Sample Space Diagrams is part of GCSE Maths Probability.

Listing outcomes and sample space diagrams are tested across GCSE probability. The key skill is organising every possible outcome so the denominator is correct before you write a probability.

QualificationGCSE Mathematics
Key stageKey Stage 4
StrandProbability
Tier guidanceFoundation: complete sample spaces · Higher: fairness and multi-step reasoning

What you will learn

  • List outcomes for simple combined events.
  • Use tables for two-way combinations.
  • Find probabilities from sample spaces.
  • Recognise equally likely outcomes.
  • Avoid double-counting.
  • Use systematic listing for multi-stage choices, ordered outcomes and fairness checks.
  • Use sample spaces to test overlapping win conditions in fair-game claims.

Why this matters

A neat sample space turns messy worded probability into visible counting.

Prior knowledge

You should already be comfortable with:

  • Fractions.
  • Tables.
  • Organised counting.

Clear explanation

Main idea

A sample space is the complete set of possible outcomes. For two coins, HH, HT, TH and TT are four equally likely outcomes because HT and TH are different orders.

Method

Use a table when two choices combine. Put one choice across the top, the other down the side, then fill every cell once. The total number of cells is the denominator only when all outcomes are equally likely.

If an outcome can happen in more than one way, do not collapse the list too early. For example, a total of 3 from two dice can be 1 then 2 or 2 then 1, so those are two ordered outcomes.

Exam tip

Write the event you are counting before the fraction. That stops you using the number of favourable outcomes as both numerator and denominator.

Sample space diagram for a coin and a spinnerA complete two-way sample space combines a coin outcome with four equally likely spinner outcomes, giving eight cells.Coin and 4-section spinner: 8 equally likely outcomesHeadsTails1234H1T1H2T2H3T3H4T4Example: P(tails and an even number) = 2 favourable cells ÷ 8 total cells = 1/4
Checked diagram: every coin-spinner pairing appears exactly once, so the denominator is 8.

Worked examples

Two coins

Find the probability of exactly one head.

Answer: Outcomes HH, HT, TH, TT. Exactly one head: HT and TH, so 2/4 = 1/2.

Fair game check

A coin is tossed and a fair spinner numbered 1 to 4 is spun. You win if the coin is tails and the spinner lands on an even number. Is the chance 1/2?

Answer: No. The favourable outcomes are T2 and T4, so the probability is 2/8 = 1/4.

Ordered dice totals

Two fair dice are rolled. How many ordered outcomes give a total of 4?

Answer: Three outcomes: (1,3), (2,2) and (3,1). The order matters because the first and second dice are separate.

Quick checks

Choose an answer, then check your thinking.

1. Two coins are tossed. Which list is complete?

2. In a 3 by 4 sample space with equally likely cells, what is the denominator?

Practice questions

Question 1

A fair dice is rolled and a fair coin is tossed. How many ordered outcomes are in the complete sample space, and what multiplication checks this?

Reveal answer and marking guidance

Answer: 12 outcomes.

Marking: There are 6 dice outcomes and 2 coin outcomes, so 6 × 2 = 12. A table with dice results down one side and coin results across the top would have 12 cells.

Question 2

Two coins are tossed in order. List the sample space and find the probability of two tails.

Reveal answer and marking guidance

Answer: 1/4.

Marking: The complete ordered sample space is HH, HT, TH, TT. Only TT is successful, so the probability is 1 out of 4.

Question 3

A fair spinner has 5 equal sections numbered 1 to 5. A fair coin is tossed. Find P(heads and an odd number).

Reveal answer and marking guidance

Answer: 3/10.

Marking: There are 2 × 5 = 10 equally likely outcomes. Heads with 1, 3 or 5 gives 3 favourable outcomes.

Question 4

A cafe offers 3 sandwich fillings and 2 breads. One filling and one bread are chosen for a lunch order. Why is a table useful?

Reveal answer and marking guidance

Answer: It shows all 6 combinations once, so none are missed or counted twice.

Marking: Mention both the total combinations and the systematic organisation.

Question 5

A fair red-blue spinner is spun twice. List the sample space and find the probability of getting one red and one blue.

Reveal answer and marking guidance

Answer: RR, RB, BR, BB; probability = 2/4 = 1/2.

Marking: RB and BR are different ordered outcomes, and both have one red and one blue.

Question 6

A meal deal has 2 mains, 3 drinks and 2 snacks. How many complete meal deals are possible?

Reveal answer and marking guidance

Answer: 12.

Marking: Multiply the choices: 2 × 3 × 2 = 12 possible meal deals.

Question 7

A fair 1 to 6 dice is rolled twice. How many ordered outcomes give a total of 7?

Reveal answer and marking guidance

Answer: 6 outcomes: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1).

Marking: Treat the first and second roll as ordered, so (1,6) and (6,1) are different outcomes.

Question 8

A bag contains cards A, B and C. Two cards are chosen in order with replacement. List the sample space and find P(two different letters).

Reveal answer and marking guidance

Answer: AA, AB, AC, BA, BB, BC, CA, CB, CC; P(two different letters) = 6/9 = 2/3.

Marking: Replacement keeps 3 choices on each draw. Count the 6 ordered pairs with different letters out of 9 equally likely outcomes.

Question 9

Two fair dice are rolled. Find the probability that the total is less than 5.

Reveal answer and marking guidance

Answer: 1/6.

Marking: Totals less than 5 are 2, 3 and 4. The ordered outcomes are (1,1), (1,2), (2,1), (1,3), (2,2) and (3,1), so 6/36 = 1/6.

Question 10

A fair spinner has equal sections numbered 1, 2 and 3. A fair coin is tossed. A player wins if the spinner lands on 2 or the coin lands on heads. Use a sample space to decide whether the game is fair.

Reveal answer and marking guidance

Answer: Not fair; P(win) = 4/6 = 2/3.

Marking: The six outcomes are 1H, 1T, 2H, 2T, 3H and 3T. Winning outcomes are 1H, 2H, 2T and 3H. Do not count 2H twice just because it satisfies both winning conditions.

Answers and marking guidance

The exact practice answers are hidden under each question so you can try first. For listing outcomes and sample space diagrams, marks usually come from showing a complete organised list or table, using the correct total number of equally likely outcomes, counting the favourable outcomes once each, and simplifying the final probability when appropriate.

Common mistakes

  • Missing ordered outcomes: HT and TH are different when the first and second toss are named in order.
  • Assuming every list is equally likely: only use count ÷ total when each outcome has the same chance.
  • Double-counting combinations: use a table or pattern so each possible result appears once.
  • Using the favourable count as the denominator: the denominator is the total number of equally likely outcomes.

Extension challenge

Create a GCSE-style question on listing outcomes and sample space diagrams, solve it, then write one sentence explaining why your method works.

Reveal answer

Example answer: A good answer includes a correct method, a checked final answer and a short reason using the key vocabulary from this lesson.

Exam-board guidance

Listing Outcomes and Sample Space Diagrams appears within the shared GCSE Maths probability content. Exact tiering and wording vary, but every board rewards complete organisation, clear event labels and a check that the outcomes are equally likely before probability calculation.

AQA GCSE Maths

Expect sample-space questions where organised lists, tables and clear fractions matter; check equally likely outcomes, ordered outcomes and fairness claims before using favourable outcomes ÷ total outcomes.

OCR GCSE Maths

Show the organised list or table, not just the final probability, especially when two or three choices are combined, order matters or a fair-game explanation is required.

Pearson Edexcel GCSE Maths

Use a complete sample space, reduce probabilities when asked and watch for ordered outcomes such as HT and TH being different results in repeated trials.

Eduqas GCSE Maths

Make your sample space visible so an examiner can see why the denominator is correct, why the game is fair or unfair, and why no outcome has been counted twice.

WJEC Wales

Use tables or lists carefully in numeracy-style contexts, then state the probability using the correct total number of possible outcomes and a clear event label.

CCEA GCSE Maths

Keep the outcome list tidy and label the event you are counting; unitised papers may mix sample spaces with fraction simplification or comparison.

Next lesson

Next, continue with Frequency Trees and Two-Way Tables.