Free GCSE Maths lesson: Probability

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Lesson 58 · GCSE / Key Stage 4 · Maths · Probability

Probability Trees

Use tree diagrams for multi-stage probability problems.

Qualification: GCSEKey Stage 4Subject: MathsStrand: Probability

GCSE specification fit

Probability Trees is part of GCSE Maths Probability.

Probability trees organise successive events. They show when to multiply along a route, when to add separate successful routes and when probabilities change after an event.

QualificationGCSE Mathematics
Key stageKey Stage 4
StrandProbability
Tier guidanceFoundation: two-stage trees · Higher: dependent events and conditional probability

What you will learn

  • Draw branches for successive events.
  • Multiply along branches.
  • Add separate successful routes.
  • Update probabilities without replacement.
  • Use tree diagrams for conditional situations.
  • Use complements and given-that information when they are quicker than adding several routes.
  • Count repeated independent routes for exactly-one and exactly-two event questions.

Why this matters

Tree diagrams make two-stage and three-stage probability questions much easier to follow.

Prior knowledge

You should already be comfortable with:

  • Fractions.
  • Multiplication.
  • Adding fractions.
  • Probability scale.

Clear explanation

Main idea

For one complete route through a tree, multiply along the branches. If there is more than one successful route, find each route probability first, then add those route probabilities.

Method

With replacement, the second-stage probabilities stay the same. Without replacement, the total goes down and the category counts may change, so the second branch fractions usually change.

For at least one or not both questions, a complement can be quicker: find the probability of the opposite event and subtract it from 1.

If a later part gives information such as the first counter was red, start from the branch that matches that information. Do not keep routes that the condition has ruled out.

For three-stage independent trees, the same rules continue: multiply along one complete route. When many routes count as success, the complement is often cleaner than listing every successful route.

Exam tip

Write the event next to the route you need. For exactly one red, the successful routes are red then blue and blue then red, so both route probabilities must be included.

Without-replacement probability treeA two-stage tree for a bag with three red counters and two blue counters shows changing second-branch fractions without replacement.Bag: 3 red, 2 blue. Pick two without replacement.R 3/5B 2/5R 2/4B 2/4R 3/4B 1/4RR = 3/10RB = 3/10BR = 3/10BB = 1/10P(exactly one red) = RB + BR = 3/10 + 3/10 = 3/5
Checked diagram: each second-branch fraction matches the counter left after the first pick.

Worked examples

With replacement

A bag has P(red) = 1/3. Two picks are made with replacement. Find P(two red).

Answer: 1/3 × 1/3 = 1/9, because the probability resets after the first pick.

Without replacement

A bag has 3 red counters and 2 blue counters. Two counters are picked without replacement. Find P(exactly one red).

Answer: RB or BR: 3/5 × 2/4 + 2/5 × 3/4 = 3/10 + 3/10 = 3/5.

Three independent trials

A test has three independent attempts, each with P(pass) = 0.7. Find P(at least one pass).

Answer: Use the complement. P(no passes) = 0.3 × 0.3 × 0.3 = 0.027, so P(at least one pass) = 1 − 0.027 = 0.973.

Quick checks

Choose an answer, then check your thinking.

1. In a tree diagram, what do you do along one route?

2. A counter is not replaced. What usually changes on the second stage?

Practice questions

Question 1

A fair coin is tossed twice. Draw or imagine the HH route on a tree diagram and find P(two heads).

Reveal answer and marking guidance

Answer: 1/4.

Marking: Multiply along the HH route: 1/2 × 1/2 = 1/4.

Question 2

On a tree diagram, P(A) = 0.4 and the branch for P(B after A) = 0.5. Find P(A and B) for that one route.

Reveal answer and marking guidance

Answer: 0.2.

Marking: Multiply along the route: 0.4 × 0.5 = 0.2.

Question 3

A tree diagram has two successful routes with probabilities 0.12 and 0.18. Explain what to do with the two routes, then find the total probability of success.

Reveal answer and marking guidance

Answer: 0.30.

Marking: Add alternative successful routes: 0.12 + 0.18 = 0.30.

Question 4

A bag has 4 red and 1 blue counters. Two counters are picked without replacement. Find P(two red).

Reveal answer and marking guidance

Answer: 3/5.

Marking: First red is 4/5, then red after red is 3/4, so 4/5 × 3/4 = 3/5.

Question 5

A bag has 3 red, 2 blue and 1 green counters. Two counters are picked without replacement. Find P(exactly one blue).

Reveal answer and marking guidance

Answer: 8/15.

Marking: Blue then not blue is 2/6 × 4/5 = 4/15. Not blue then blue is 4/6 × 2/5 = 4/15. Add the routes: 8/15.

Question 6

A biased spinner has P(win) = 0.3 on each spin. It is spun twice independently. Find P(at least one win).

Reveal answer and marking guidance

Answer: 0.51.

Marking: Use the complement: P(no wins) = 0.7 × 0.7 = 0.49, so P(at least one win) = 1 − 0.49 = 0.51.

Question 7

A bag has 5 red and 3 blue counters. Two counters are taken without replacement. Given that the first counter was red, find the probability that the second counter is blue.

Reveal answer and marking guidance

Answer: 3/7.

Marking: The condition puts you on the first red branch. There are then 4 red and 3 blue counters left, 7 in total, so P(blue second | red first) = 3/7.

Question 8

A tree has three independent trials, each with P(success) = 0.2. Find P(at least one success).

Reveal answer and marking guidance

Answer: 0.488.

Marking: Use the complement: P(no successes) = 0.8 × 0.8 × 0.8 = 0.512, so P(at least one success) = 1 − 0.512 = 0.488.

Question 9

A bag has 6 red and 4 blue counters. Two counters are taken without replacement. Given that the two counters are different colours, find the probability that the first counter was red.

Reveal answer and marking guidance

Answer: 1/2.

Marking: Different colours can be RB or BR. P(RB) = 6/10 × 4/9 = 4/15 and P(BR) = 4/10 × 6/9 = 4/15. Given different colours, P(first red) = P(RB) ÷ (P(RB) + P(BR)) = (4/15)/(8/15) = 1/2.

Question 10

A player takes three independent shots. The probability of scoring on each shot is 0.4. Find P(exactly two scores).

Reveal answer and marking guidance

Answer: 0.288.

Marking: There are three successful routes: score-score-miss, score-miss-score and miss-score-score. Each route has probability 0.4 × 0.4 × 0.6 = 0.096, so 3 × 0.096 = 0.288.

Answers and marking guidance

The exact practice answers are hidden under each question so you can try first. For probability trees, marks usually come from drawing or completing the branches correctly, labelling replacement or no-replacement probabilities, multiplying along each route, adding alternative successful routes and simplifying or rounding the final probability as requested.

Common mistakes

  • Adding along a route: multiply along one route; add only after route probabilities have been found.
  • Forgetting replacement: with replacement probabilities stay the same, but without replacement the second-stage fractions usually change.
  • Counting one route for exactly one event: exactly one red means red then not red and not red then red.
  • Dropping branch labels: labels make it clear which probability belongs to which route.

Extension challenge

Create a GCSE-style question on probability trees, solve it, then write one sentence explaining why your method works.

Reveal answer

Example answer: A good answer includes a correct method, a checked final answer and a short reason using the key vocabulary from this lesson.

Exam-board guidance

Probability Trees appears within shared GCSE probability content. The same core method applies across boards: branch labels first, route calculations second, final probability last, with replacement decisions checked before any arithmetic.

AQA GCSE Maths

Label each branch probability, multiply along a route and add separate successful routes; check replacement before writing any second-stage fraction.

OCR GCSE Maths

Make the tree structure clear enough to follow; questions often reward the branch setup, route multiplication, route addition and final interpretation separately.

Pearson Edexcel GCSE Maths

Write the changing fractions on without-replacement branches and simplify only after the multiply-and-add structure is clear.

Eduqas GCSE Maths

Describe the event you are finding, then use the tree to show which route or routes count as success before adding them.

WJEC Wales

Expect probability trees in contextual problems; keep replacement, no replacement and given-that language separate before choosing branch probabilities.

CCEA GCSE Maths

Use branch labels and route working to make your method visible; watch whether the question asks for one route, several routes added together, a complement or a conditional result.

Next lesson

Next, continue with Independent and Dependent Events.